Curve equation for this shape??

[rajib]

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[jraquet]

If you use a polar graph,you can use these values to relate theta and r to get something like this:


theta = t*90 (theta goes from 0 to 90 degrees)


r = sin(theta)*cos(theta)

 

[jraquet]

Here is first order (given above) and then extras created with powers of the r variable (sqrt(r), r, r*r)





View attachment 4677

 

[jraquet]

You can create a closer shape with arcs:


(light blue) the darker shape is created with the polar equations.


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